000-512 Exam

Quality and Value for the 000-512 Exam

4cert Practice Exams for IBM 000-512 are written to the highest standards of technical accuracy, using only certified subject matter experts and published authors for development.

Guarantee to Pass Your 000-512 Exam

If you prepare for the exam using our 4cert testing engine, we guarantee your success in the first attempt. If you do not pass the Solutions Expert 000-512 Exam exam (db2 udb v7.1 family fundamentals) on your first attempt we will give you a FREE UPDATE of your purchasing fee AND send you another same value product for free.

IBM 000-512 Exams (in EXE format)

Our Exam 000-512 Preparation Material provides you everything you will need to take your 000-512 Exam. The 000-512 Exam details are researched and produced by Professional Certification Experts who are constantly using industry experience to produce precise, and logical. You may get questions from different web sites or books, but logic is the key. Our Product will help you not only pass in the first try, but also save your valuable time.

000-512 Downloadable, Interactive Testing engines

We are all well aware that a major problem in the IT industry is that there is a lack of quality study materials. Our Exam Preparation Material provides you everything you will need to take a certification examination. Like actual certification exams, our Practice Tests are in multiple-choice (MCQs) Our IBM 000-512 Exam will provide you with exam questions with verified answers that reflect the actual exam. These questions and answers provide you with the experience of taking the actual test. High quality and Value for the 000-512 Exam:100% Guarantee to Pass Your Solutions Expert exam and get your Solutions Expert Certification.
　
　
Exam : IBM 000-512
Title : db2 udb v7.1 family fundamentals


1. Given the following SQL statements:
CREATE TABLE tab1 (col1 INT)
CREATE TABLE tab2 (col1 INT)
INSERT INTO tab1 VALUES (NULL),(1)
INSERT INTO tab2 VALUES (NULL),(1)
SELECT COUNT(*) FROM tab1
WHERE col1 IN
(SELECT col1 FROM tab2)
Which of the following is the result of the SELECT COUNT(*) statement?
A. 1
B. 2
C. 3
D. 4
E. 0
Answer: A

2. Given the two following tables:
Names
Name Number
Wayne Gretzky 99
Jaromir Jagr 68
Bobby Orr 4
Bobby Hull 23
Brett Hull 16
Mario Lemieux 66
Steve Yzerman 19
Claude Lemieux 19
Mark Messier 11
Mats Sundin 13
Points
Name Points
Wayne Gretzky 244
Jaromir Jagr 68
Bobby Orr 129
Bobby Hull 93
Brett Hull 121
Mario Lemieux 189
Joe Sakic 94
Which of the following statements will display the player Names, numbers and points for all players with an entry in both tables? Which of the following statements will display the player? Names, numbers and points for all players with an entry in both tables?
A. SELECT names.name, names.number, points.points FROM names INNER JOIN points ON names.name=points.name
B. SELECT names.name, names.number, points.points FROM names FULL OUTER JOIN points ON names.name=points.name
C. SELECT names.name, names.number, points.points FROM names LEFT OUTER JOIN points ON names.name=points.name
D. SELECT names.name, names.number, points.points FROM names RIGHT OUTER JOIN points ON names.name=points.name
E. SELECT names.name, names.number, points.points FROM names FULL OUTER JOIN points ON names.name=points.name
F. SELECT names.name, names.number, points.points FROM names LEFT OUTER JOIN points ON names.name=points.name
G. SELECT names.name, names.number, points.points FROM names RIGHT OUTER JOIN points ON names.name=points.name
H. SELECT names.name, names.number, points.points FROM names LEFT OUTER JOIN points ON names.name=points.name
I. SELECT names.name, names.number, points.points FROM names RIGHT OUTER JOIN points ON names.name=points.name
J. SELECT names.name, names.number, points.points FROM names LEFT OUTER JOIN points ON names.name=points.name
K. SELECT names.name, names.number, points.points FROM names RIGHT OUTER JOIN points ON names.name=points.name
Answer: A

3. Which of the following describes why savepoints are NOT allowed inside an atomic unit of work?
A. Atomic units of work span multiple databases, but savepoints are limited to units of work which operate on a single database.
B. A savepoint implies that a subset of the work may be allowed to succeed, while atomic operations must succeed or fail as a unit.
C. A savepoint requires an explicit commit to be released, and commit statements are not allowed in atomic operations such as compound SQL.
D. A savepoint cannot be created without an active connection to a database, but atomic operations can contain a CONNECT as a sub-statement.
Answer: B

4. Given a table T1, with a column C1 char(3), that contains strings in upper and lower case letters, which of the following queries will find all rows where C1 is the string 'ABC' in any case?
A. SELECT * FROM t1 WHERE c1 = 'ABC'
B. SELECT * FROM t1 WHERE UCASE(c1) = 'ABC'
C. SELECT * FROM t1 WHERE IGNORE_CASE(c1 = 'ABC')
D. SELECT * FROM t1 WHERE c1 = 'ABC' WITH OPTION CASE INSENSITIVE
Answer: B

5. Given the tables:
COUNTRY
ID NAME PERSON CITIES
1 Argentina 1 10
2 Canada 2 20
3 Cuba 2 10
4 Germany 1 0
5 France 7 5
STAFF
ID LASTNAME
1 Jones
2 Smith
The statement:
SELECT * FROM staff, country
will return how many rows?
A. 2
B. 4
C. 5
D. 7
E. 10
Answer: E

http://www.4cert.com The safer.easier way to get Solutions Expert Certification.